The provided acid base reaction is as follows: CH;CH20 H20 + Compare the pK values of...

 

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The provided acid base reaction is as follows: CH;CH20 H20 + Compare the pK values of ethanol and water (Refer to Table 2.2 in the text book). For CH¸CH,OH pK¸ =15.9 and for water pK =15.7 Ethanol has a higher pK, value than water. So conjugate base of ethanol, ethoxide ion must be a base and water with lower pK should be an acid. In this solution. why used the pKa of CH3CH,OH instead of the pKa of CH;CH20 ??? Water didn't use the pKa of H30*. P.S. Please answer with the typing not handwrithing as possible The provided acid base reaction is as follows: CH;CH20 H20 + Compare the pK values of ethanol and water (Refer to Table 2.2 in the text book). For CH¸CH,OH pK¸ =15.9 and for water pK =15.7 Ethanol has a higher pK, value than water. So conjugate base of ethanol, ethoxide ion must be a base and water with lower pK should be an acid. In this solution. why used the pKa of CH3CH,OH instead of the pKa of CH;CH20 ??? Water didn't use the pKa of H30*. P.S. Please answer with the typing not handwrithing as possible

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The pk is the acid ionization constant of an acid We are comparing the acidity of e... View the full answer