The pump shown in the figure below delivers a head of $150$ ft to the water. Determine the power that the pump adds to the water. The difference in elevation of the two ponds is $100$ ft $.$

Assume $L=500ft,D=0\mathrm{.}75ft.$

Pipe length $=L$

Pipe diameter $=D$

Pipe roughness $=0$

$W_S^{}=$

$ft*l\frac{b}{s}$ or

hp