Question: The p-value is * The Decision is 0 Accept the null hypothesis.There is a significant difference between the sample mean and the population mean. Accept






















The p-value is * The Decision is 0 Accept the null hypothesis.There is a significant difference between the sample mean and the population mean. Accept the null hypothesis.There is no significant difference between the sample mean and the population mean. Reject the null hypothesis. There is a significant difference between the sample mean and the population mean. Reject the null hypothesis. There is no significant difference between the sample mean and the population mean. The test statistic used is * The value of the test statistic is * ' 0 none of these The null hypothesis is * - The kind of test is * . _ O one-tailed 0 two tailed A random sample of 100 school administrators were conducted a Training Course. The sample mean and standard deviation were 90 and 5 respectively. In the standardization of the test, the mean was 85 and the standard deviation of 6. Test the significant difference using a=0.05 utilizing the p-value method.The pvalue is . * O none of these The Decision is Reject the null hypothesis. There is no 0 significant difference between the sample mean and the population mean. Accept the null hypothesisThere is no significant difference between the sample mean and the population mean. Reject the null hypothesis. There is a significant difference between the sample mean and the population mean. Accept the null hypothesis.There is a significant difference between the sample mean and the population mean. The sample proportion is * The value of the test statistic is * The alternative hypothesis is The kind of test is * O one-tailed 0 two tailed The test statistic to be used is 0 none of these Mr. B asserts that fewer than 5% of the battery that he sells are defectives. Suppose 200 battery are randomly selected, each are tested and 8 defective batteries are found. Does this provide sufficient evidence for Mr. B to conclude that the fraction of defective batteries is less than 0.05? Use a=0.01 and the p-value approach. The null hypothesis is O p>0.05 O p0.40
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