Question: The quadratic equation x ^ 2 + (3k + 1) * x + (4 - 9k) where k is constant, has repeated roots. A) Show

The quadratic equation x ^ 2 + (3k + 1) * x + (4 - 9k) where k is constant, has repeated roots. A) Show that 9k ^ 2 + 42k - 15 = 0 First part of the question. This is what I need answering - part B = b) hence find the possible value of k

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