Question: the question is : if a solution containing 37.90 g or mercury(II) chlorate is allowed to react completely with a solution containing 9.718g of sodium

the question is : if a solution containing 37.90 g or mercury(II) chlorate is allowed to react completely with a solution containing 9.718g of sodium dichromate, how many grams of solid precipitate will be formed?
and you have to find the answers to the following:
the question is : if a solution containing 37.90 g or mercury(II)

Question 6 of 6 > mass: How many grams of the reactant in excess will remain after the reaction? 8 mass Assuming complete precipitation, how many moles of each ion remain in solution? If an ion is no longer in solution, enter a zero (O) for the number of moles, mol Hg? TOOLS x10 mol CIO Na mol Cr, 02 mol treer McQuam, Rock And Galloly 4 General Chemistry Publisher University Science 800

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