The random variable x has the following discrete probability distribution. X 10 11 12 13 14 p(x) 0.3 0.3 0.1 0.2 0.1 Since the values that x can assume are mutually exclusive events, the event {x $ 12} is the union of three mutually exclusive events, {x = 10)U(x = 11)U(x= 12). Complete parts a through e. a. Find P(x $ 12). P(xS 12) = b. Find P(x > 12). P(x> 12) = c. Find P(x s 14). P(XS 14) = d. Find P(x = 14). P(x = 14)= e. Find P(x S 11 or x > 12). P(x s 11 or x > 12)=