The reaction: 2A+2B yields D+F was studied carefully and the following mechanism was finally determined to...

 

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The reaction: 2A+2B yields D+F was studied carefully and the following mechanism was finally determined to be the following: A+A yields C (Slow) C+B yields D+E (fast) E+B yields F (very Fast) The rate law for the reaction would therefore be: A. Rate=k[A]^2 B. Rate=k[A]^2[B]^2 C. Rate=k[C][B] D. Rate=k[A][B]^3 E. Rate=k[A][B} The reaction: 2A+2B yields D+F was studied carefully and the following mechanism was finally determined to be the following: A+A yields C (Slow) C+B yields D+E (fast) E+B yields F (very Fast) The rate law for the reaction would therefore be: A. Rate=k[A]^2 B. Rate=k[A]^2[B]^2 C. Rate=k[C][B] D. Rate=k[A][B]^3 E. Rate=k[A][B}

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The reaction equation is 2A 20 D F Mechanism slow step fast step fastest step A A CB DE ... View the full answer