The resistanceless inductor is connected across the ac source whose voltage amplitude is $30\mathrm{.}0V$ and angular frequency is $900ra\frac{d}{s}.$ Find the current amplitude if the self$-$inductance of the inductor is

Part A

$1\mathrm{.}00{10}^{-2}H.$

Express your answer in amperes.

$I_A=$

A

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Part B

$1\mathrm{.}00H.$

Express your answer in milliamperes.

$I_B=$