Question: The resolving power of an electron microscope is approximately equal to the de Broglie wavelength of the electrons. If the resolving power of an electron

The resolving power of an electron microscope is approximately equal to the de Broglie wavelength of the electrons. If the resolving power of an electron microscope is 0.01 nm, find the kinetic energy (in the unit of keV) of the electrons used. (Please use the equation p = h/mv where p is the momentum, is the Lorentz factor, m is the mass and v is the velocity)

(5 marks)

Express the values to 3 significant figures, if necessary.

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