Question: The restoring force a spring that does not obey HOOKE'S law is F ( x ) = - a x - b x 2 ,

The restoring force a spring that does not obey HOOKE'S law is F(x)=-ax-bx2, where a=60Nm,B=18Nm2 and the mass of spring can be negligible. Find the potential energy difference of the spring
The restoring force a spring that does not obey

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