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The reversible reaction, A + B = C + D, is carried out adiabatically in a series of staged packed-bed reactors with inter stage cooling. The lowest temperature to reactant system may be cooled is 27 C. The feed is equal molar in A and B and the catalyst weight in each reactor is sufficient to achieve 99.9% of the equilibrium conversion. The feed enters at 27 C and the reaction is carried out adiabatically. Additional information cal AHRX = -30,000- mol A cal Cp,A Cp,B = Cpc = Cp,D = 25; mol. K mol A K (50C) = 500,000, and FAO = 10 min a- Derive an expression for the rate law b- Derive an expression for the equilibrium conversion c- Derive an expression for the reaction temperature d- Derive an expression for the equilibrium conversion from energy balance e- Plot equilibrium conversion versus reaction temperature f- What would the reaction temperature and conversion be at equilibrium if the reactant enters at 27 C g- for the first coolers, how much heat must be removed to cool the reactant system from the exit temperature of the first reactor to 350 and h- How many reactors and interstage coolers are required to achieve 90% conversion You may use Excel for your calculations =