The rms $($root$-$mean$-$square$)$ speed of a diatomic hydrogen molecule at $50$C$$C is $2000$ m$/$sm$/$s$.$ Note that $1\mathrm{.}0$ molmol of diatomic hydrogen at $50$C$$C has a total translational kinetic energy of $4000$ JJ$.$

Part A

Diatomic oxygen has a molar mass $16$ times that of diatomic hydrogen. The root$-$mean$-$square speed vrmsvrms for diatomic oxygen at $50$C$$C is:

Choose the correct value of vrmsvrms$.$

View Available Hint$($s$)$for Part A

$(16)(2000$m$/$s$)=32000$m$/$s$(16)(2000$m$/$s$)=32000$m$/$s$(4)(2000$m$/$s$)=8000$m$/$s$(4)(2000$m$/$s$)=8000$m$/$s$2000$m$/$s$2000$m$/$s$(14)(2000$m$/$s$)=500$m$/$s$(14)(2000$m$/$s$)=500$m$/$s$(116)(2000$m$/$s$)=125$m$/$s$(116)(2000$m$/$s$)=125$m$/$snone of the above

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Part B

The total translational kinetic energy of $1\mathrm{.}0$ mole of diatomic oxygen at $50$C$$C is:

Choose the correct total translational kinetic energy.

View Available Hint$($s$)$for Part B

$(16)(4000$J$)=64000$J$(16)(4000$J$)=64000$J$(4)(4000$J$)=16000$J$(4)(4000$J$)=16000$J$4000$J$4000$J$(14)(4000$J$)=1000$J$(14)(4000$J$)=1000$J$(116)(4000$J$)=150$J$(116)(4000$J$)=150$Jnone of the above

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Part C

The temperature of the diatomic hydrogen gas sample is increased to $100$C$$C$.$ The root$-$mean$-$square speed vrmsvrms for diatomic hydrogen at $100$C$$C is:

Choose the correct vrmsvrms$.$

$(2)(2000$m$/$s$)=4000$m$/$s$(2)(2000$m$/$s$)=4000$m$/$s$(2)(2000$m$/$s$)=2800$m$/$s$(2)(2000$m$/$s$)=2800$m$/$s$2000$m$/$s$2000$m$/$s$(12)(2000$m$/$s$)=1400$m$/$s$(12)(2000$m$/$s$)=1400$m$/$s$(12)(2000$m$/$s$)=1000$m$/$s$(12)(2000$m$/$s$)=1000$m$/$snone of the above