The rocket is fired vertically and tracked by the radar station shown. When $$ reaches $66,$ other corresponding measurements give the values $r=37300ft,r^{}=69f\frac{t}{se{c}^2},$ and ${}^{}=0\mathrm{.}013ra\frac{d}{sec}.$ Calculate the magnitudes of the velocity and acceleration of the rocket at this position.

Answers:

$v=1,f\frac{t}{sec}$

$a=0,f\frac{t}{se{c}^2}$