the same problem with the problem below, except that the top surface is ponded with water to a depth of $H_p.$ Find $q$ and plot $h$ as a function of $z.$

Roblem$2$: Now the wil cotumn has wo willigen. In the kplunt $)\text{'}$

thas $n_1,c_1*c_2+4(1)$

$tan{H}_1=C_{4}x+C_6(2)$

Mensiry conditions for the top liyvr:

A

Denday conditions for the botem leyer:

For the $h$ prodila $n_1-h+x$ when :$z-h$

When $-(t_1+t_1)2-L_1$

$-\frac{La(K_n-K_n)}{L_n+L{K}_n}+\frac{(L+4L)}{L{K}_n+4K_n}$

$=\frac{(K_1-K_n)}{L_4{K}_1+L_1{K}_n}(L_2+L_4+L_2)$

Uning the above buadary cosdition$,$ we will hive:

$c_i=0,N_i=c_i$

For $=-(L_1+L_2)*H_4=-C_2(L_1+4_2)+C_3=-(4_1+4)$

$($:$c_4=(L_1+L_3)c_1-1\}$

When :$=4.4.$

$n_4=-c_4{L}_4=-c_4{L}_4+(L_4+L_{2}x{c}_4-n)-u_3$

Than, $c_1=\frac{4+4}{4}-\frac{4}{4}{c}_1$ sq$($s$)$

Now trom the continuily.

Combinise with cq$-9),$ we can rasily obtain

$c_1=(L_1+L_7)\frac{x_n}{L_2{x}_n+I_1{x}_2}$

$c_4=(4+2)\frac{x_n}{L_4{x}_4+4x_4}$