The solid rod AB has a diameter of $70$ mm

and is made of steel for which the ultimate

shearing stress is $170$ MPa $.$ The pipe CD$,$

which has an outer diameter of $95mm$ and a

wall thickness of $8mm$ made of aluminum for

which the allowable shearing stress is $45$

MPa.

Given:

LCD$=0\mathrm{.}7m$

LAB$=0\mathrm{.}2m$

The factor of safety will be $2\mathrm{.}5$

$G_{\text{s}\text{t}\text{e}\text{e}\text{l}}=74$ Gpa

$G_{\text{a}\text{l}\text{u}\text{m}\text{i}\text{n}\text{u}\text{m}}=24$ Gpa

Determine the polar moment of inertia for pipe

$CD{J}_{CD}=417248m{m}^4$

One possible correct answer is: $4172481\mathrm{.}15$

Determine the largest torque $T$ that can be

applied at point $A,T=3\mathrm{.}95$ KN$.$m

One possible correct answer is: $3\mathrm{.}95$

If the $T$ is $6\mathrm{.}5KN.m$ Determine the angle of

twist at point $B,{}_B=$ degree

One possible correct answer is: $2\mathrm{.}6$

If the $T$ is $6\mathrm{.}5KN.m$ Determine the angle of

twist at point $A,{}_A=$

degree