The solid spindle $AB$ has a diameter $d_S=1\mathrm{.}5in.$ and is made of a steel with an allowable shearing stress of $18$ ksi $,$ while

sleeve $CD$ is made of a brass with an allowable shearing stress of $7$ ksi $,$ outer diameter a $=2\mathrm{.}8in.$ and thickness $t=0\mathrm{.}15in.$

Determine the allowable torque $T$ that can be applied at $A.$

Using FBD$/$equilibrium equations for appropraite cut sections between $A$&$B$ and between C&D$,$

the magnitude of the internal reaction $T_{AB}=$

$T$ and

the magnitude of the internal reaction $T_{CD}=$

$T$