The solution for the linear equations:

$a_{1}x+b_{1}y=c_1$

$a_{2}x+b_{2}y=c_2$

Marking scheme

is given by $x=\frac{b_2{c}_1-b_1{c}_2}{a_1{b}_2-a_2{b}_1}$

$y=\frac{a_1{c}_2-a_2{c}_1}{a_1{b}_2-a_2{b}_1}$

With the condition that $a_1{b}_2-a_2{b}_{1}0$

Write a C$++$ program which calculates these solutions $x$ and $y$

$\backslash$table$[[$Part$],[$Documentation$,1],[$Compiler directives,$0\mathrm{.}75],[$Program structure,$1],[$Main function,$0\mathrm{.}75],[$Comments$,1],[$Input$,1],[$Output$,13],[$Variables declaration,$3\mathrm{.}5],[$Formulae$,8]]$

$($a$)$ Prompt the user for the real coefficients $a_1,b_1,a_2,b_2,c_1$ and $c_2$

$($b$)$ Calculate the solution $x$ and $y$ taking into account the condition mentioned above.

The result should display as shown on the screen below: