Question: The solution to LPP give below is Max Z = 3X_{1}, 14X_{2} subject to X_{1} - X_{2} >= 1 2X_{1} - 3X_{2} = 0 solution

The solution to LPP give below is Max Z = 3X_{1}, 14X_{2} subject to X_{1} - X_{2} >= 1 2X_{1} - 3X_{2} <= 0 where X_{1}, X_{2} >= 0 solution b. Max Z = 14 cMaxZ = 3 d. Infeasible solution

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