Question: The specification for a certain dimension is 3.000 = 0.004 in. A large sample from the process indicates an average of 2.998 in. and a

The specification for a certain dimension is 3.000 = 0.004 in. A large sample from the process indicates an average of 2.998 in. and a standard deviation of 0.002 in. Suppose that controls are instituted to shift the process average to the nominal specification of 3.000. Each part outside specification limits results in a loss of $5. In a lot of 1000 parts, how much money would be saved by shifting the average versus keeping it at 2.998? The specification for a certain dimension is 3.000 = 0.004 in. A large sample from the process indicates an average of 2.998 in. and a standard deviation of 0.002 in. Suppose that controls are instituted to shift the process average to the nominal specification of 3.000. Each part outside specification limits results in a loss of $5. In a lot of 1000 parts, how much money would be saved by shifting the average versus keeping it at 2.998
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