Question: The standard deviation alone does not measure relative variation. For example, a standard deviation of $1 would be considered large if it is describing the
The standard deviation alone does not measure relative variation. For example, a standard deviation of $1 would be considered large if it is describing the variability from store to store in the price of an ice cube tray. On the other hand, a standard deviation of $1 would be considered small if it is describing store-to-store variability in the price of a particular brand of freezer.
A quantity designed to give a relative measure of variability is the coefficient of variation. Denoted by CV, the coefficient of variation expresses the standard deviation as a percentage of the mean. It is defined by the following formula.
CV = 100(s/x)
Consider two samples. Sample 1 gives the actual weight (in ounces) of the contents of cans of pet food labeled as having a net weight of 8 ounces. Sample 2 gives the actual weight (in pounds) of the contents of bags of dry pet food labeled as having a net weight of 50 pounds. The weights for the two samples are as follows.
| Sample 1 | 9.6 | 8.2 | 8.8 | 9.6 | 8.8 |
|---|---|---|---|---|---|
| 9.6 | 9.9 | 8.1 | 8.1 | 8.8 | |
| Sample 2 | 51.0 | 51.2 | 51.1 | 52.4 | 51.7 |
| 47.0 | 50.4 | 50.3 | 48.7 | 48.2 |
(a)
For each of the given samples, calculate the mean and the standard deviation. (Round your standard deviations to four decimal places.)
Sample 1
MeanStandard Deviation
Sample 2
MeanStandard Deviation
(b)
Calculate the coefficient of variation for each sample. (Round your answers to two decimal places.)
CV1CV2
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