The stress intensity factor $K$ at a crack is given by $K=C\sqrt[\phantom{2}]{a}$ where $$ is the far$-$field stress, $a$ is the crack length, and $C$ is a parameter that depends on the geometry of the specimen and crack. For the case of the edge crack shown in the figure, $C$ is given by:

$C=\frac{1-\frac{\frac{a}{b}}{2}+0\mathrm{.}326(\frac{a}{b}{)}^2}{\sqrt[\phantom{2}]{1-\frac{a}{b}}}$

Write a script file that will print out a table of values with the ratio $\frac{a}{b}$ in the first column and the corresponding parameter $C$ in the second column. Let $\frac{a}{b}$ range between $0\mathrm{.}05$ and $0\mathrm{.}80$ with increments of $0\mathrm{.}05.$