Question: The surface charge, o, for oxide minerals is given by the following equation o=(RTF)ln(C+/C+o)pH=log[H+] R= natural gas constant (1.98cal/K-mole) n= valence (equivalence /mole) F= Faraday's

The surface charge, o, for oxide minerals is given by the

The surface charge, o, for oxide minerals is given by the following equation o=(RTF)ln(C+/C+o)pH=log[H+] R= natural gas constant (1.98cal/K-mole) n= valence (equivalence /mole) F= Faraday's constant (23,060cal/ volt-equiv) C+=concentration of potential determining ion in solution C+o= concentration of potential determining ion at the T= temperature (K) point of zero charge What would be the expected surface charge for SiO2 at a solution pH 6? Assume the value of n (valence/mole) is that of hydrogen ion (+1)

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