Question: The surface z = 4 x 2 + y 2 is a cone with axis of symmetry along the z-axis and vertex (0, 0, 4).

The surface z = 4 x 2 + y 2 is a cone with axis of symmetry along the z-axis and vertex (0, 0, 4).

Consider the solid E enclosed by this cone and z = 0 (that is, the xy-plane). Let D be the region where this solid intersects z = 0. The volume of E can be expressed as the following double integral over the region D: Vol(E) = ZZ D 4 q x 2 + y 2 dA. By converting this integral to polar coordinates, find the volume of E

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