The switch in the circuit in $($Figure $1)$ has been open a long time before closing at $t=0.$

Figure

$1$ of $1$

Find $i_L(t)$ for $t0$

$0\mathrm{.}2+0\mathrm{.}5e^{-200t}+e^{-800t}A$

$0\mathrm{.}1+0\mathrm{.}5e^{-200t}+0\mathrm{.}5e^{-800t}A$

$0\mathrm{.}2+0\mathrm{.}5e^{-200t}-e^{-800t}A$

$0\mathrm{.}1+0\mathrm{.}5e^{-200t}-0\mathrm{.}5e^{-800t}A$

$0\mathrm{.}2+0\mathrm{.}5e^{-200t}-0\mathrm{.}5e^{-800t}A$

$0\mathrm{.}2+0\mathrm{.}5e^{-200t}+0\mathrm{.}5e^{-800t}A$

$0\mathrm{.}1+0\mathrm{.}5e^{-200t}-e^{-800t}A$

$0\mathrm{.}1+0\mathrm{.}5e^{-200t}+e^{-800t}A$

Request Answer

Part B

Find $v_C(t)$ for $t0.$

$-25e^{-200t}-100e^{-800t}V$

$-50e^{-200t}-200e^{-800t}V$

$-50e^{-200t}+200e^{-800t}V$

$-25e^{-200t}+200e^{-800t}V$

$-50e^{-200t}-100e^{-800t}V$

$-50e^{-200t}+100e^{-800t}V$