The system shown in the figure includes a pump that transfers high$-$pressure oil to the hydraulic motor, which drives an external load through a rotary shaft. The data given are as follows. Pump: $7$m $=94\%$ hydraulic motor: nm $=92\%$ n $=92\%$ Vth $=120$ cm$^3$ nv $=90\%$ Vth $=100$ cm$^3$ n $=1000$ rpm motor discharge pressure $=35$ Kpa inlet pressure $=-27$ KPa pump discharge pressure $=4\mathrm{.}0$ MPa Elvo loss factor K$=0\mathrm{.}75,$ check valve loss factor K$=4\mathrm{.}0,$ oil viscosity $=125$ x$10^-6$ m$^2/$s$,$ oil specific gravity $=0\mathrm{.}9.$ Specific gravity of water $=9800$N$/$m$^3$ If the hydraulic motor is $5$ m above the pump, calculate: $(1)$ pump flow rate $[$answer : $1\mathrm{.}84$x$10^-3$ m$^3/$s$](2)$ Input hp $[$answer : $11\mathrm{.}49$hp$](3)$motor speed $[$answer : $996$ rpm$](4)$ motor drive pressure P $2[$answer : $3660$ Kpa$](5)$ motor output hp $[$answer : $7\mathrm{.}4$ hp$](6)$ motor output torque $[$answer : $52\mathrm{.}9$ N$.$m$]$