Question: the table below. 36 - 41 in 42 - 47 in 48 - 53 in 54 - 59 in 50 -59 4 4 2 0

the table below. 36 - 41 in 42 - 47 in 48 - 53 in 54 - 59 in 50 -59 4 4 2 0 lbs4 60 - 69 lbs 10 5 2 U 70 - 79 lbs 6 6 5 5 80 - 89 Ibs 4 6 9 8 90 - 99 Ibs 0 3 7 100 - 109 0 lbs 0 2 One student is chosen at random. Determine the following probability: P(choosing someone 80 - 89 lbs. OR 36 - 41 in) Recall the formula: Addition Rule: P(A or B) = P(A) + P(B) - P(A and B)
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
