Question: The table just needs to be filled in with test cases, no coding is required!!! The code below repeats the bump method from the above.

The table just needs to be filled in with test cases, no coding is required!!!
The code below repeats the bump method from the above. bump will increase by one the priority for all items associated with a given customer. def bump(self, customer: str) None: "" "Increases by one the priority of all items attributed to the specified customer." "" for index in range(self. length()): if self.items[index]['customer'] == customer: self.items[index][ 'priority'] +=1 Add four different test cases to the table below to thoroughly test the method bump . The code below will generate a queue, which you should use for your answers. The case should match the given input. The list has been printed for reference. ]: leather_list = LWPriorityQueue() leather_list.insert(1, 'belt', 'Steff', 45) leather_list.insert(2, 'wallet', 'stock', 60) leather_list.insert(2, 'wallet', 'Mo', 60) leather_list.insert(2, 'wallet', 'stock', 60) leather_list.insert(3, 'custom belt', 'Erich', 90) print(leather_list.print_queue())
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