Question: The task is below. You cannot use any library methods and please use simple code to complete this. To do this, create a separate array
The task is below. You cannot use any library methods and please use simple code to complete this. To do this, create a separate array that does not include repeated elements, so there are no duplicates (only one of each element in a given array). Then, use for loop and nested for loop to see if the number in the array at j is equal to the number in the no-repeat array at i. Thanks! And please, check the code and test cases work.
NOTE: the method should not print anything in the console. It should just return a result. (Use )

TEST CASES:

STARTING CODE:
public static String countArray (int[] array) {
}
Write a method countArray that takes an array of integers as a parameter. The method checks the integers that are even and in the range 2 inclusive to 100 exclusive and counts how many occurrences of each are in the array. The method should return a string that has all the values in the array along with the number of their occurrences in the array. For example: if the array has the following values: [2,10,10,98,3,146], the method should count the occurrence of integers that match the condition above. The string returned should be as follows (use ): ' 2:1 10:2 98: 1 " If the array is empty, the returned string should be empty
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
