The test statistic in a left$-$tailed test is $z=0\mathrm{.}99.$ Determine the $P-$value and decide whether, at the $1\%$ significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis.

Click here to view a partial table of areas under the standard normal curve.

The $P-$value is

$($Round to four decimal places as needed.$)$

This $P-$value sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis because it is the significance level.