The thickness h of a sheet of sea ice as a function of time t satisfies the equation:

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dh dt . Ta is the air temperature, Heat escapes through the ice ● Tw is the water temperature, ice Thin layer of water freezes as .k is the thermal conductivity of the ice, heat escapes L is the latent heat of the water, and water • D is the mass density of the water. In this question we will assume that Ta, Tu, k, L, and D are constants. We measure the thickness of a sheet of sea ice daily, and observe that it is 3 cm on day 0, and 5 cm on day 10. Determine when the thickness of the sheet will be 13 cm. for h> 0 where k LDh (Tw - Ta) air

Expert Answer

We have given that dh dt ?_ (??-??) = LDh We simplify it hah= K (Tw-Ta…View the full answer

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