Question: The time interval between customer arrivals during rush hour to a drive-in window with one teller is exponentially distributed with a mean of 1 minute.
The time interval between customer arrivals during rush hour to a drive-in window with one teller is exponentially distributed with a mean of 1 minute. Congestion occurs during rush hour, and only this period is to be analyzed. The time it takes a car from arrival to the drive-in entrance is normally distributed with a mean of 0.5 minutes and a standard distribution of 0.2 minutes. The service time at the drive-in window is normally distributed with a mean of 1.2 minutes and a standard deviation of 0.3 minutes. It takes a Normal (0.5, 0.2) minute to drive from the entrance (or the window) to the departure from the system.
Because of space limitations, only three cars (in addition to the one being served) can wait in the lane. If there are less than three cars waiting in the queue or on the way to the drive-in window, an incoming car (at the drive-in entrance) joins the queue and gets serviced when its turn comes. If, however, the system is full when a customer arrives at the drive-in entrance, s/he drives around the block and tries to get in. If after driving around, the system is still full s/he leaves and is lost to the system. Time to drive around the block (to the drive-in entrance) is uniformly distributed with a minimum of 3 minutes and a maximum of 5 minutes.
draw a simple simulation layout of the above system on paper.
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