The time interval between samples is h=0.5 hour. When the process mean shifts to 1.725 microns. Use equation (6.19), the probability of x falling between the control limits in (a) is approximately = ((1.51.725)/ (0.15 /5)+3.0902)((1.51.725)/ (0.15 /5)3.0902)=0.39593? (3pts Therefore, in this case, the out of control ARL (called ARL1) is 1/(10.39593)=1.65543 (3pts) The average time required to detect this shift is (called ATS 1 ) is 1/(10.39593)0.5=0.82771 (3pts)