Question: The time needed for performing a machining operation is to be investigated. Historically, the process has had a standard deviation equal to 0.177 minutes. The
The time needed for performing a machining operation is to be investigated. Historically, the process has had a standard deviation equal to 0.177 minutes. The means (in minutes) of 39 samples of n = 6 are:
| Sample | Mean | Sample | Mean | Sample | Mean |
| 1 | 3.78 | 14 | 3.74 | 27 | 3.80 |
| 2 | 3.75 | 15 | 3.77 | 28 | 3.68 |
| 3 | 3.69 | 16 | 3.88 | 29 | 3.90 |
| 4 | 3.80 | 17 | 3.70 | 30 | 3.54 |
| 5 | 3.91 | 18 | 3.81 | 31 | 3.74 |
| 6 | 3.78 | 19 | 3.70 | 32 | 3.88 |
| 7 | 3.98 | 20 | 3.83 | 33 | 3.66 |
| 8 | 3.88 | 21 | 3.82 | 34 | 3.62 |
| 9 | 3.96 | 22 | 3.81 | 35 | 3.50 |
| 10 | 3.90 | 23 | 3.72 | 36 | 3.64 |
| 11 | 3.95 | 24 | 3.71 | 37 | 3.98 |
| 12 | 3.95 | 25 | 3.98 | 38 | 3.84 |
| 13 | 3.90 | 26 | 3.89 | 39 | 3.79 |
The average of the 39 sample means is equal to 3.80.
a. Construct an xx -chart for this process with two-sigma limits. (Round the final answers to 2 decimal places.)
| UCL | LCL | ||
| Mean Control Limits | |||
b. Is the process in control?
multiple choice
-
Yes
-
No
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
