Question: The top node had 10 high taste items and 20 not high taste items. We determined the Gini score should be .5555. For the H2S

The top node had 10 high taste items and 20 not high taste items. We determined the Gini score should be .5555. For

The top node had 10 high taste items and 20 not high taste items. We determined the Gini score should be .5555. For the H2S > 7 split, the > 7 child had 7 of 10 high and 3 of 10 not high. We determined the Gini score to be .58. The This program will calculate purity measures for a leaf node and display the Gini score and other values calculated. Please enter the number of objects in this leaf node of type I 7 Please enter the number of objects in this leaf node of type II 3 The Gini score for this node is 0.580 Assume that P() is the proportion or probability of an object of one type occurring. The formula for the Gini score is : Gini = (P(Type I objects))2 + (P(Type II objects))2 This program will calculate purity measures for a leaf node and display the Gini score and other values calculated. Please enter the number of objects in this leaf node of type I 7 Please enter the number of objects in this leaf node of type II 3 The Gini score for this node is 0.580 Assume that P() is the proportion or probability of an object of one type occurring. The formula for the Gini score is : Gini = (P(Type I objects))2 + (P(Type II objects))2

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