Question: The truss shown is subject to two loads P = 5 kN applied at joint A and 2.5 kN applied at joint B. The

The truss shown is subject to two loads P = 5 kN applied at joint A and 2.5 kN applied at joint B. The two applied loads resulted in the internal forces shown. Tension positive (T) and Compression negative (C). The cross-sectional area of each member is 100 mm and E = 200 GPa for all members. For the loading shown, use the Virtual Force Method: (a) Find the vertical deflection of joint A (Av). (b) Find the horizontal deflection of joint A (AH). Tabulate your calculations as shown below. k nNL Principle of Virtual Work: 1.4= 5 kN -2.4 m B 2.5 kN -2.4 m 2.4 m 2.236P (T) 2.00P (C) 2.4 m VONZ 2.236P+2.795 (T) B 2.5 kN 2.795 kN (C) 2.00P (C) 2.4 m www 2.4 m

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