The value obtained for the test statistic, z, in a one-mean z-test is given. Whether the test is two tailed, left tailed, or right tailed is also specified. For parts (a) and (b), determine the P-value and decide whether, at the

55%

significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis.

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Part 1

a. The test statistic in a left-tailed test is

zequals=negative 2.362.36.

The P-value is

. 009.009.

(Round to three decimal places as needed.)

Part 2

At the

55%

significance level, the data

provides

sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis because the obtained P-value is

less than

the significance level.

Part 3

b. The test statistic in a left-tailed test is

zequals=0.920.92.

The P-value is

enter your response here.

(Round to three decimal places as needed.)