Question: The vector field 6 . x . cos (3 . x2) F = -6 . y . sin (3 . y2) is conservative with potential

The vector field 6 . x . cos (3 . x2) F = -6 . y . sin (3 . y2) is conservative with potential function f(x, y) = cos(3 . y2) + sin(3 . x2) a Curve C is equal to the circle with radius 1 and the center at the origin, with a parameterization r (t) that goes once around the curve counterclockwise. SC F . dr. Calculate the working integral Answer: b) Curve D is the part of the circle in a) that lies in the first quadrant (ie where x20 and y20), with a parameterization that goes from point to point (clockwise). Calculate the working integral JD F . dr
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