The vertices of a AABC are A (4, 6), B (1, 5) and C (7, 2)....
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The vertices of a AABC are A (4, 6), B (1, 5) and C (7, 2). A line is drawn to intersect AD AE 1 == sides AB and AC at D and E respectively, such that AB AC 4. Calculate the area of the AADE and compare it with the area of AABC. (Recall Converse of basic proportionality theorem and Theorem 6.6 related to ratio of areas of two similar triangles) = The vertices of a AABC are A (4, 6), B (1, 5) and C (7, 2). A line is drawn to intersect AD AE 1 == sides AB and AC at D and E respectively, such that AB AC 4. Calculate the area of the AADE and compare it with the area of AABC. (Recall Converse of basic proportionality theorem and Theorem 6.6 related to ratio of areas of two similar triangles) =
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