Question: The voltage across a load is v ( t ) = 1 0 4 2 cos ( t + 1 0 ) Vv ( t

The voltage across a load is v(t)=1042cos(t+10)Vv(t)=1042cos(t+10)V, and the current through the load is i(t)=282cos(t40)Ai(t)=282cos(t40)A. The reference direction for the current points into the positive reference for the voltage.
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Part E
Is this load inductive or capacitive?

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