The voltage drop through resistors #$1$ and #$2$ is the same, but resistor #$1$ has two times greater resistance than resistor #$2.$

The power dissipated in resistor #$1$ is:

$\frac{1}{2}$ the power dissipated in resistor #$2.$

$\frac{1}{4}$ the power dissipated in resistor #$2.$

$q,$ The same as power the dissipated in resistor #$2.$

$$ Four times the power dissipated in resistor #$2.$

$$ Twice the power dissipated in resistor #$2.$

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