THE WIND CHILL PROBLEM

As all Midwest residents know, both the temperature and wind speed combine to give a temperature called the wind chill. The "standard" formula used to calculate wind chill $($w$),$ for a given temperature $($t$,$ in degrees F$)$ and wind speed $($v$,$ in MPH$)$ is

$w=\mathrm{.}0817**(3\mathrm{.}71**\sqrt[\phantom{2}]{v}+5\mathrm{.}81-\mathrm{.}25**v)**(t-91\mathrm{.}4)+91\mathrm{.}4$

This results in wind chill tables as helow $($from $($JSA Todav$)$:

Here are several tasks that you can use to practice your Matlab skills.

A$.$ Calculate the wind chill $($WC$)$ for a single temp & wind speed $($and compare it to table above to make sure it is correct$)$ Repeat for a different temp & wind speed.

B$.$ Make plot of WC versus WindSpeed

A$.$ Make a vector of wind speeds $($from $10-50MPH$ in steps of $5)$

B$.$ Calculate WC for these speeds at a given temperature $($will need to use array arithmetic$)$

C$.$ Plot curve of WindSpeed versus WC for this temperature

D$.$ Calculate WC for another temperature & overlay on this graph

E$.$ Label your graph appropriately

C$.$ Repeat the previous plots with the same two temperatures for speeds of $10-300MPH$

Submit

The two answers for $A$

The labeled graph for B with the two windspeed$/$wind$-$chill curves

The labeled graph for $C$ with the two windspeed$/$wind$-$chill curves

A brief statement on the difference between the two graphs $($B & C$)$ above $-$ do they make sense? Why or why not? Do some web research...

Attempt in Octave$/$MATLAB $($May try in EXCEL first to get a solution$)$