Question: The work function for aluminum is 4 . 0 8 eV . ( a ) Find the cutoff wavelength for aluminum. nm ( b )

The work function for aluminum is 4.08 eV.
(a) Find the cutoff wavelength for aluminum.
nm
(b) What is the lowest frequency of light incident on aluminum that releases photoelectrons from its surface?
Hz
(c) If photons of energy 5.61 eV are incident on aluminum, what is the maximum kinetic energy of the ejected photoelectrons?
eV

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