Then, immediately at time t$3=25\mathrm{.}3$ ms on the stopwatch, switch S$3$ is thrown open and switch s$4$ is closed $($switch S$2$ remains closed and S$1$ remains open$).$ The system is then allowed to reach the steady state. At this steady state, find:

$($k$).$ The charge $($in uC$)$ on C$1$

$24362454320301320936$

$($l$).$ The charge $($in uC$)$ on C$2$

$259447116298971629$

$($m$).$ The charge $($in uC$)$ on C$3$

$259447116298629971$

$($n$).$ The voltage $($in V$)$ across C$1$

$8\mathrm{.}1517\mathrm{.}74\mathrm{.}725\mathrm{.}4311\mathrm{.}52\mathrm{.}12$

$($o$).$ The voltage $($in V$)$ across C$2$

$17\mathrm{.}74\mathrm{.}728\mathrm{.}152\mathrm{.}125\mathrm{.}4311\mathrm{.}5$

$($p$).$ The voltage $($in V$)$ across C$3$

$11\mathrm{.}52\mathrm{.}125\mathrm{.}438\mathrm{.}154\mathrm{.}7217\mathrm{.}7$

$($q$).$ The energy $($in mJ$)$ in C$1$

$1\mathrm{.}693\mathrm{.}572\mathrm{.}540\mathrm{.}6591\mathrm{.}475\mathrm{.}51$

$($r$).$ The energy $($in mJ$)$ in C$2$

$1\mathrm{.}211\mathrm{.}700\mathrm{.}8070\mathrm{.}3150\mathrm{.}7022\mathrm{.}63$

$($s$).$ The energy $($in mJ$)$ in C$3$

$2\mathrm{.}630\mathrm{.}7021\mathrm{.}210\mathrm{.}8070\mathrm{.}3151\mathrm{.}70$

$($t$).$ The total energy $($in mJ$)$ on all three capacitors.

$1\mathrm{.}294\mathrm{.}952\mathrm{.}873\mathrm{.}306\mathrm{.}9610\mathrm{.}8$

$($Compare this answer to that for question $($j$).$ Does this surprise you? It should. This is a relatively famous paradox that physics journal submissions and Masters theses have been written to try and explain$$ mostly unsatisfactorily$).$