There is no way you will miss NBA games on your road trip! You want to...
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There is no way you will miss NBA games on your road trip! You want to know some stats for popular NBA players. Write a function dct_op that takes in a dictionary (the player's name (strings) as the key and a list of total game points (integers) as value) and a function func. Your function should apply function func to each integer in the list and return an updated dictionary. Assume the input func always takes in an integer and returns another integer. Note: You can solve this problem using one-line dictionary comprehensions in the format below. You are not required to but it is very similar to list comprehensions, so give it a try! This link might be helpful. (key: value for (key, value) in iterable} Example: >>> example = (x:x+10 for x in [1,2,3,4,5]} >>> print (example) (1: 11, 2: 12, 3: 13, 4: 14, 5: 15) def update_stats (dct, func): 111111 >>> dct = {'Curry': [26, 21, 30], 'James': [26, 22, 18]} >>> update_stats (dct, squared) {'Curry': [676, 441, 900], 'James': [676, 484, 324]} >>> dct = {'Poole': [15, 11, 27, 23], 'Tatum': [35, 21, 22, 28], \ 'Harden': [28, 11, 22, 19]} >>> update_stats (dct, identity) {'Poole': [15, 11, 27, 23], 'Tatum': [35, 21, 22, 28], \ 'Harden': [28, 11, 22, 19]} >>> update_stats (dct, lambda x: x + 1) {'Poole': [16, 12, 28, 24], 'Tatum': [36, 22, 23, 29], \ 'Harden': [29, 12, 23, 20]} www There is no way you will miss NBA games on your road trip! You want to know some stats for popular NBA players. Write a function dct_op that takes in a dictionary (the player's name (strings) as the key and a list of total game points (integers) as value) and a function func. Your function should apply function func to each integer in the list and return an updated dictionary. Assume the input func always takes in an integer and returns another integer. Note: You can solve this problem using one-line dictionary comprehensions in the format below. You are not required to but it is very similar to list comprehensions, so give it a try! This link might be helpful. (key: value for (key, value) in iterable} Example: >>> example = (x:x+10 for x in [1,2,3,4,5]} >>> print (example) (1: 11, 2: 12, 3: 13, 4: 14, 5: 15) def update_stats (dct, func): 111111 >>> dct = {'Curry': [26, 21, 30], 'James': [26, 22, 18]} >>> update_stats (dct, squared) {'Curry': [676, 441, 900], 'James': [676, 484, 324]} >>> dct = {'Poole': [15, 11, 27, 23], 'Tatum': [35, 21, 22, 28], \ 'Harden': [28, 11, 22, 19]} >>> update_stats (dct, identity) {'Poole': [15, 11, 27, 23], 'Tatum': [35, 21, 22, 28], \ 'Harden': [28, 11, 22, 19]} >>> update_stats (dct, lambda x: x + 1) {'Poole': [16, 12, 28, 24], 'Tatum': [36, 22, 23, 29], \ 'Harden': [29, 12, 23, 20]} www
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To create the updatestats function that takes a dictionary of player names and their game points and applies a given function func to each game point ... View the full answer
Related Book For
Taxation Of Individuals And Business Entities 2016
ISBN: 9781259334870
7th Edition
Authors: Brian Spilker, Benjamin Ayers, John Robinson, Edmund Outslay, Ronald Worsham, John Barrick, Connie Weaver
Posted Date:
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