Question: These questions beyond 3D really confuse me any help would be greatly appreciated. I'll paste the entire question below. V G. 10. a. ii) The

These questions beyond 3D really confuse me any help would be greatly appreciated. I'll paste the entire question below.

These questions beyond 3D really confuse me anyThese questions beyond 3D really confuse me any V G. 10. a. ii) The equation x ty +z +t' = rad defines a (hyper)sphere of radius rad in four dimensions. Use a system of double polar coordinates and the appropriate volume conversion factor to give a formula that measures the four dimensional volume of this (hyper) sphere of radius rad.Tip: Agreeing that R stands for everything inside and on the four dimensional sphere of radius rad, you will also agree that its volume is SSS, axdydzat . Double polar coordinates mean: Clear [x, y, z, t, r, s, u, v, rad]; x [r_, s_ V_] = r Cos[s] ; y [r_, s_ , u_, v_] = r Sin[s]; z [r_, S_, u_, = u Cos [v] ; t [r_, s_, u V_ = u Sin[v] ; You let s and v run from 0 to 2 it, and to see what r and u do, substitute into x - ty +z' +t' = rad' : TrigExpand [x [r, s, u, v]^2 + y[r, s, u, v]^2 + z[r, s, u, v]^2 + t[r, s, u, v]^2] == rad^2 ro + u" == rad This tells you to put r[p, q] = p Cos[q], and u[p, q] = p Sin[q], to let p run from 0 to rad, and to let q run from 0 to Watch to be sure that your volume conversion factor stays positive. This hypersphere does not have 4D volume 0

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