This algorithm will multiple a number by repeatedly adding the value of A the number of times stated in the value of B$.$

For example, if A $=10$ and B $=3,$ This algorithm will perform the following :

$10+10+10=30$

Tip: Notice that this only added the value of A $3$ times but in your response, you will see it shows up to $4$ iterations.

If this happens in any of these exercises, the proper answer would be "Loop Ended" for both Count and Product.

A $=5$ B $=4$

Get A

Get B

STEP $1$ If A or B $=0$

Then Set Product to $=0$ and Go To STEP $3$

Else Set Count to $0$ and Set Product to $0$ and Go To STEP $2$

STEP $2$ While Count $<$ B

Set Product to $($Product $+$ A$)$

Set Count to $($Count $+1)$

End of Loop;

STEP $3$ Print the value of Product

STEP $4$ Stop

After Iteration $1$:

Count equals

Product equals

After Iteration $2$:

Count equals

Product equals

After Iteration $3$:

Count equals

Product equals

After Iteration $4$:

Count equals

Product equals