This equation shows how much AlCl3 can be produced with 22.0g of Al. 22.0g Al x (1
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This equation shows how much AlCl3 can be produced with 22.0g of Al.
22.0g Al x (1 mol Al/26.98g) x (2 mol AlCl3/2mol Al) x (133.34 g/1 mol AlCl3) = 108.66g AlCl3
This equation shows how much AlCl3 can be produced with 27.0g of Cl2.
27.0g Cl2 x (1 mol Cl2/70.91g) x (2mol AlCl3/3 mol Cl2) x (133.34g/1 mol AlCl3) = 33.87g AlCl3
This shows that chlorine is the limiting reactant. Only 33.87 grams of AlCl3 can be produced before the chlorine will run out.
Related Book For
Essentials of Materials Science and Engineering
ISBN: 978-1111576851
3rd edition
Authors: Donald R. Askeland, Wendelin J. Wright
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