This exercise is based on the following functions. Fx) = x2 + 3 with domain (-0, +00) 9(x) = x - 3 with domain (-0, +0) h(x) = x + 6 with domain [39, +) u(x) = x + 39 with domain (-39,0) v(x) = 67 - x with domain (0, 67) For a = - = 3, do the following. (a) Write a formula for the indicated function. g(x) = (b) Give the function's domain. (Enter your answer using interval notation.) (c) Specify the function's value at the given point a = 3, if defined. (If an answer is undefined, enter UNDEFINED.) 9(3) =