Question: This goes with my previous question. Any help is appreciated Urses/72871/assignments/2086840 Citi = rith Ci-1 = Ci- h yit1 = yj th yj-1 = yj
This goes with my previous question. Any help is appreciated

Urses/72871/assignments/2086840 Citi = rith Ci-1 = Ci- h yit1 = yj th yj-1 = yj - h Knowing the value of a two-dimensional function f - f (x, y) at each node in the mesh, your objective is to calculate the partial derivatives da ps of and dy at node (Ii, y;) [Note that, in this example, the mesh sizes in x and y are identical (h); strictly speaking, this need not be true. In some applications, we may need more resolution along the x- or y-axis; we could then use separate mesh sizes hx and hy.] By definition, the partial derivative of a function f (x, y) with respect to x is - Limn (z,th, y;)-f (zi,y,) and the partial derivative with respect to y is of - Limn-40 dy S ( 2, y, th) 1 (1,y;) h If we applied these formula to our grid values, we would get the finite difference expressions h Note that these are approximations to the values of the partial derivatives, since we're not taking the limit as h goes to zero; but as h becomes smaller, the approximations should improve
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