This graph represents uphill and downhill

You are given only the info $y=y(xk)-y(xk-1)$ and that $f^{\text{'}}(x)=\frac{y}{x}$

If $x(x)=\{\begin{array}{cc}1,& f^{\text{'}}(x)>0\\ 0,& f^{\text{'}}(x)<mn>0</mn>\end{array}$

Than what is the value of $x(x)$ up hill and down hill

Uphill $=?$

downhill $=?$